Ïðîäîëæåíèå òåìû. Ñòàðàÿ òåìà ïî ññûëêå
http://www.cqham.ru/forum/showthread...=1#post1549667
Ïðîäîëæåíèå òåìû. Ñòàðàÿ òåìà ïî ññûëêå
http://www.cqham.ru/forum/showthread...=1#post1549667
Ñïàñèáî îò Ventil
Âîò èíòåðåñíûé ìàòåðèàë îòíîñèòåëüíî òîãî, êàêèì îáðàçîì ìîæíî áûëî áû îïðåäåëèòü íîìèíàëû ðåçèñòîðà è êîíäåíñàòîðà "ãðèäëèêà":
http://www.antiqueradios.com/forums/...60023&start=20Ñêðûòûé òåêñò
Here's how I determine the values for the grid capacitor and leak resistor for the regenerative detector -
1. Make the value of the grid capacitor (condenser) around ten times the total input capacitance of the tube grid (grid to plate plus grid to cathode). This makes the impedance of the capacitor, at the carrier frequency, small in comparison with that of the grid.
2. The time constant of the grid leak and condenser should be no greater than one fifth of the period of the highest modulating frequency to be reproduced, in order for the grid voltage to follow the modulation envelope quickly enough to not reduce the amplitude and distort the waveform of the recovered modulating frequency excessively.
Using these guidelines, the values can be determined:
1. Choose the condenser value:
For example, the grid input capacitance of tube type '01A is published as very close to 11 pF. So, 10 x 11 = 110 pF. The closest common value is 100 pF, it will work perfectly well here.
2. Calculate the maximum value for the grid leak:
If the highest modulating frequency to be reasonably well reproduced is say, 3500 Hz, then 1/3500 = 286 uS. 286/5 = 57 uS. 57 uS divided by 100 pF = 571,429 ohms as the maximum for the grid leak. The closest standard 10% value is 560 k.
So, 100 pF for the condenser and 560 k ohms for the grid leak are suggested, in the example case given.
Of course, experimentation with values up to two or three times higher and lower may be appealing so as to develop a feel for the effect they may have on the audio, regeneration control, sensitivity, etc.
Êðàòêîå ñîäåðæàíèå, ñóòü:
1. Âåëè÷èíà åìêîñòè îðèåíòèðîâî÷íî â 10 ðàç âûøå, ÷åì ñóììàðíàÿ åìêîñòü (ñåòêà-êàòîä + ñåòêà-àíîä) ëàìïû.
2. Âåëè÷èíà ñîïðîòèâëåíèÿ âûáèðàåòñÿ èñõîäÿ èç ïîñòîÿííîé âðåìåíè RC-öåïî÷êè ãðèäëèêà, êîòîðàÿ äîëæíà ñîñòàâëÿòü íå áîëåå îäíîé ïÿòîé ïåðèîäà ìàêñèìàëüíîé ÷àñòîòû ìîäóëÿöèè.
Ïðèìåð:
1. Äëÿ ëàìïû 6Æ8 åìêîñòü ãðèäëèêà ñîñòàâëÿåò ïðèìåðíî 10 õ (6 + 7) = 130 ïô.
2. Äëÿ ýòîé æå ëàìïû è ìàêñèìàëüíîé ÷àñòîòû ìîäóëÿöèè 6êÃö (ïåðèîä = 1/6000 = 167ìêñ, îäíà ïÿòàÿ áóäåò 33ìÊñ, äåëèì íà åìêîñòü 130 ïô, ïîëó÷àåì ìàêñèìóì 254 êÎì.
Ýòî òå îðèåíòèðîâî÷íûå çíà÷åíèÿ, ñ êîòîðûõ íóæíî íà÷èíàòü, à ïðàêòè÷åñêîå èçìåíåíèå ýòèõ ïàðàìåòðîâ â 2-3 ðàçà òóäà-ñþäà ïîäñêàæåò, êàê ïîëó÷èòñÿ ëó÷øå.
Ïîñëåäíèé ðàç ðåäàêòèðîâàëîñü sgk; 28.07.2018 â 10:26. Ïðè÷èíà: ßçûê ôîðóìà ðóññêèé.
Ïðè ìàêåòèðîâàíèè ìîæíî èñïîëüçîâàòü íàáîð åìêîñòåé è ñîïðîòèâëåíèé, êîììóòèðîâàòü äæàìïåðàìè â ëþáîé êîìáèíàöèè. È ïðîáîâàòü ïðè ðàçëè÷íûõ ðåæèìàõ êàñêàäà.
Ïîçäðàâëÿþ âñåõ ñ 8 âåòêîé òåìû!
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Ñîîáùåíèÿ ðàíåå îá îòáîðå ëàìï
http://www.cqham.ru/forum/showthread...=1#post1549611
http://www.cqham.ru/forum/showthread...=1#post1549650
äëÿ ðàáîòû â ñõåìå ðåãåíåðàòîðà ñ "áàòàðåéíûì" ïèòàíèåì. Ïîä áàòàðåéíûì íàïðÿæåíèåì ïîíèìàåòñÿ 12,6  íàïðÿæåíèå àêêóìóëÿòîðà èç äâóõ áàíîê ïî 6,3 Â. Îñòàâøèåñÿ 6 ëàìï 6Æ1Ï ïðîâåðèë ïðè íàïðÿæåíèè àíîäíîé öåïè 21  - 26 Â.  ðåçóëüòàòå 4-ðå ëàìïû çàðàáîòàëè â ñõåìå ðåãåíåðàòîðà (èíäóêòèâíàÿ òð¸õòî÷êà) íî ñî ñìåùåíèåì 0,1  èëè âûøå íà ïåðâóþ ñåòêó. Äâå ëàìïû íå çàðàáîòàëè. Ïîïðîáîâàë äëÿ ñõåìû ðåãåíåðàòîðà ëàìïû 6Æ52Ï. Îäíà èç ëàìï çàðàáîòàëà ïðè àíîäíîì +26  è ñìåùåíèè 0,1  íà ïåðâîé ñåòêå.  îáùåì ïðèîáðåòåíèå Á/Ó ëàìï íà ðûíêå äëÿ ðàáîòû ñ íèçêèì àíîäíûì íàïðÿæåíèåì ëîòåðåÿ, ïîâåç¸ò èëè íå ïîâåç¸ò.
Ñïàñèáî îò standby
Êîãäà òî çàäàâàëñÿ âîïðîñ - áûëè ëè ïðîìûøëåííûå îáðàçöû ïðèáîðîâ ñ íèçêèì àíîäíûì. Åñòü ÈÐÊ-2 - Èñïûòàòåëü ðàäèîêîìïàñîâ, ïèòàåòñÿ îò áîðòñåòè àâèàòàõíèêè 27  +- 10%.  íåì Ä - Ñ Â× ãåíåðàòîð ñ ìîäóëÿòîðîì íà äâóõ ïàëü÷èêîâûõ ëàìïàõ, óìôîðìåðà íåò, àíîäíîå - 27 Â. Ïðèáîð èìååòñÿ, ÒÎ íåò, äîáåðóñü - ïîñìîòðþ, êàêèå ëàìïû.
Êðîìå ïðîñòî ëþáîïûòñòâà ïðè êàêîì àíîäíîì íàïðÿæåíèè ìîæåò ðàáîòàòü ëàìïà â ñõåìå ðåãåíåðàòîðà äëÿ ýòîãî ñïåöèàëüíî íå ïðåäíàçíà÷åííàÿ, åñòü æåëàíèå çàïèòàòü ñõåìó îò USB ïîðòà íîóòáóêà. Ýòî 5  áåç êàêèõ ëèáî ïðåîáðàçîâàòåëåé.
Òàêîé ëàìïû íåò, íà ðàäèîðûíêå ëàìïû ýòîé ñåðèè áûëè òàêèå ðæàâûå ÷òî ïîêóïàòü íå ñòàë. Ïðè ñëó÷àå è íàëè÷èè ðàáî÷åé ëàìïû ïðîâåðþ. Ïîêà ðåçóëüòàòû òàêèå: íàïðÿæåíèå íàêàëà 5  (íàïðÿæåíèå â ñëó÷àå ïèòàíèÿ îò USB) íåêîòîðûå ëàìïû 6Í1Ï ðàáîòàþ ïðè àíîäíîì 10-12  è íóâèñòîðû 6Ñ52Í. Ëàìïà 6Í23Ï ðàáîòàåò îò 0,5  àíîäíîãî è íàêàëüíîì 5 Â. Íðàâèòñÿ ëàìïà 6Æ1Ï èç-çà "ìåíüøåãî" òîêà íàêàëà (0,17 À) â ñðàâíåíèè ñ 6Í23Ï. Íî íå ìîãó çàñòàâèòü ðàáîòàòü ýòîò ýêçåìïëÿð ïðè 5  àíîäíîãî. Ðàáîòàåò ïðè 5,8  àíîäíîãî è ïîëîæèòåëüíîì ñìåùåíèè íà ïåðâóþ ñåòêó. Íàêàë 5 Â.
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